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If an integer n is to be chosen at random from the integers

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If an integer n is to be chosen at random from the integers 1 to 96, inclusive, what is the probability that n(n + 1)(n + 2) will be divisible by 8?
A. 1/4
B. 3/8
C. 1/2
D. 5/8
E. 3/4

3 Answers

kapil_1255
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Now only 2 choices are left :-)
answered Jun 29, 2016 by Beginner (16 points)
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Bofua Bruno - You are correct. Now go ahead and post your solution for a meaningful takeaway for everyone.
answered Jun 29, 2016 by (-1 points)
dkrishna
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C it has to be... any n(n+1)(n+2) will always be divisible by 2. And if we pick any even number as n then n+2 will always be divisible by 4 if n is not divisible by 4. Hence whenever n is even the term will be divisible by 8.
answered Jun 29, 2016 by Beginner (11 points)
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