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# : PS When positive integer A, which has n digits, is

Open 2 Answers 35 Views
Veritas: PS
When positive integer A, which has n digits, is multiplied by (n+2), the product is a number with (n+1) digits, all of whose digits are (n+1). How many instances of A exist?
(a) None
(b) 1
(c) 2
(d) 8
(e) 9

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Final term 333??? if your multiplying with n+2 then it should be 24 * 22 right ?? (if n=22)
answered Jun 22, 2016 by Student (31 points)
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Since 'n+1 is a single digit number' n cannot be equal to 9 i.e n*9
if n=0 , then A has 0 digits. Not possible. Hence n*0.
answered Jun 22, 2016 by (-1 points)
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