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If integer C is randomly selected from 20 to 99, inclusive. What is the probability

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If integer C is randomly selected from 20 to 99, inclusive. What is the probability that C^3 - C is divisible by 12 ?
A. 1/2
B. 2/3
C. 3/4
D. 4/5
E. 1/3
Official Answer

1 Best Answer

Rk
3
Best answer
If n is even or if n+1 is div by 4
Out of every four nos from 20,21,22,23 upto 96,97,98,99;  2 are even and 1 n+1 is div by 4 and these are exclusive to each other. Thus prob = 3/4
answered Sep 2, 2014 by Student (51 points)
selected Sep 10, 2014 by
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Jyotsna Mehta

Indian School of Business, Co'18

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